OK,
I’m going to perform a huge leap forward in theory after examining the board pictures and (trying) to thoroughly read the data sheet for the LTC1629CG-PG ICs.
Short answer: You have a short in your system, AFTER the regulation circuitry we’ve been looking at, that’s why your 3.3v lines wiggles at the PSU and why ALL MOSFET drains measure so low and all the same value. The regulators are fighting to control what’s happening and limit damage and current. Now the short could be in something you have to attach to the board to make it function (another card or PCB board). But something on the line regulated by the MOSFETs is shorted.
I’ll explain better, but all the regulators and all the MOSFETs are actually one, big, regulator (see datasheet, page 26). They are all regulating the same line as multiple “phases”. Phases in this sense isn’t like AC phases, it’s momentary on/off power that is shared by all the regulators to share thermal load for high-current applications to produce the rapid on/off switching pattern, like a switching PSU (DC), to create the new DC signal, but using several parallel components as a collective group, to emit power quickly in-turn (like round-robin) fashion to share the thermal load using a very quick time-slices. Think GPU VRMs or CPU VRMs.
Data sheet is here:
https://www.analog.com/media/en/technica.../1629f.pdf
Printed page 26, describes the multiple controller layout (albeit with 6 MOSFETs on each controller instead of the 4 you have at each controller in your picture). You have two controllers with 4 MOSFETs each, total of 8 MOSFETS, but I believe this is counted as 4 phases (works in pairs).
OK, my explanation of my theory:
Just like a bench power-supply in current limited-mode, (though the overcurrent documentation isn’t too clear on the datasheet). When you exceed the maximum current rating, the regulators will show a voltage drop, the more severe the draw the bigger the voltage drop, lower the voltage value. In your case, I don’t know what the regulator is set for, is could be set for 1.6v, 3.3v, or higher (datasheet is unclear how Vout is set and has multiple graphs with several different Vout voltages, so this is unclear, I don’t know what yours is set for.
Since all MOSFETs are regulating the same line they are all in overload.
Something appears to be overdrawing a DC current that is present on AC plug-in alone. This short is happening while just plugged into the wall, without trying to power-on the system. The short is in stuff that just runs all the time (like the L1 circuitry).
The 3.3v (or the like) voltage rail is being pulled down to 0.188v DC, this appears to be a “Stable” short. Easiest solution is to get a thermal imager (even a cheaper phone-attachment model like a thermal seek would do). Look at “hot stuff” while the system is just on standby power and you should see one or more locations that light up. Look for the brightest first but look at all areas that come up. Then inspect for heat…lots of heat means lots of current dissipation. Hopefully you locate your short and it’s not a custom IC or something.
OR you could so buy a current tracer probe for less than a thermal imager on the used market but it’s harder to use.
OR you can use the dangerous bench PSU method to find the short:
Using a bench power supply, you set the voltage to something very low (don’t want to over-volt anything) like 1v-1.5v to start at 2A power. You locate the output of the regulator circuit (which very close to the coil output (but there is a beware issue here, some have 0Ohm shunt resistors on them to help measure current draw, those can blow, you want to do this after all 0,00, or 000 labelled SMD resistors, or green resistor/fuses) and on an unpowered, unplugged, separated from the system board, you apply power to the voltage rail that’s in short with the bench PSU, and watch the bench PSU display to see if the voltage just drops to 0v while the current Maxs out.
Then you know you have a short and use either your fingers or several different chemicals (like freeze-spray, rubbing alcohol, zippo light fluid, etc) to try to detect very hot spots on the board as you apply power to the shorted rail. You can increase the Amperage, but you don’t want to actually fully burn out the component that is shorted or it will go fully open and then draw nothing and unless it explodes, you’ll then never find it.
So, the trick is to heat it up (without breaking it) and try to find the bad component either by thermal touch, thermal imaging, or solution reaction to heat.
Also be aware if you remove the board and get NO current draw reaction from the bench PSU test, nor any thermal imaging hot-spots, then the short isn’t on that board…but on something else that is plugged into that board! You have to follow the boards (doing the same thing or the like, to track down the physical area with the shorted component that’s drawing down the entire regulated DC rail on this path.
To easily test the idea of the short being in another system component, get a kill-a-watt or other AC draw measuring device for your AC wall socket. And you could start to try to, slowly, unplug AC, remove a board or component, and reattach to the wall AC socket, check kill-a-watt meter for the power draw. If I’m right this power is really being drawn, so the meter should show like a few amps or something? Keep removing pieces with system off and unplug PSU every time you make a change, and reattach AC power. Maybe you can locate a CPU card, or add-in card, or something where the meter shows a sudden drop in current after you remove a piece of the system that isn’t on this board.
But again, if the short is on this board, then it really will be present all the time, if it’s an attachment, then changing the attachment would remove the short from the system and it would function again.
Kill-a-watts are like $25 or something...cheap to try, cool to have.
Anyway, that’s my theory, see what you can come up with.